Question

problem 2
here is a partially
fill in the missing d
calculations.
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$$\begin{array}{r}\\ 8\\ \\square\\\\6\\overline{)5\\ 3\\ 4}\\\\-\\ \\square\\ \\square\\\\\\hline\\ \\ \\ \\ \\square\\ \\square\\\\\\ \\ \\ -\\ \\square\\ \\square\\\\\\hline\\ \\ \\ \\ \\ \\ \\ \\ 0\\end{array}$$

\\

Explanation:

Step1: Calculate 6×8

First, we know that the first digit of the quotient is 8. We multiply the divisor 6 by 8: $6\times8 = 48$. So the first subtraction is 53 - 48.

Step2: Find the remainder after first subtraction

Calculate 53 - 48: $53 - 48 = 5$. Then we bring down the 4 from the dividend, making the new number 54.

Step3: Determine the second digit of the quotient

We need to find a number x such that 6×x = 54. Solve for x: $x=\frac{54}{6}=9$. So the second digit of the quotient is 9. And the subtraction here is 54 - 54 = 0.

Answer:

The completed division is:

$
equire{enclose}

$$\begin{array}{r} 8\ 9 \\ 6 \enclose{longdiv}{5\ 3\ 4} \\ \underline{4\ 8\ \ \ } \\ \ 5\ 4 \\ \ \underline{5\ 4} \\ \ \ 0 \\ \end{array}$$

$

The missing digit in the quotient is 9, the first subtraction numbers are 4 and 8, the number after bringing down is 5 and 4, and the last subtraction numbers are 5 and 4.