Question

$\angle vbc \cong \angle dcb$ & $\overline{vb} \cong \overline{dc}$ \
prove: $\triangle bvc \cong \triangle cdb$ \
statement \\t reason \
drag & drop the answer \
$\overline{bc} \cong \overline{bc}$ \\t $\angle vbc \cong \angle dcb$ & $\overline{vb} \cong \overline{dc}$ \\t reflexive property \\t $\triangle bvc \cong \triangle cdb$ \
given \\t sss \\t sas \\t asa \\t aas \\t hl \
cpctc \
note: use ctrl+o to drag the option via keyboard

Explanation:

Step1: List given congruences

$\angle VBC \cong \angle DCB$, $\overline{VB} \cong \overline{DC}$

Step2: Identify shared side

$\overline{BC} \cong \overline{BC}$ (Reflexive Property)

Step3: Apply SAS congruence

Two sides + included angle match, so $\triangle BVC \cong \triangle CDB$ via SAS.

Answer:

STATEMENT	REASON
$\overline{BC} \cong \overline{BC}$	Reflexive Property
$\triangle BVC \cong \triangle CDB$	SAS