Question

if a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true? the figure must be an isosceles trapezoid because it has 2 congruent base angles. the figure could be a rhombus because the 2 lines of symmetry bisect the angles. the figure could be a square because the diagonals of a square bisect the right angles. the figure must be a rectangle because all rectangles have exactly 2 lines of symmetry.

Explanation:

A quadrilateral with exactly 2 lines of symmetry, both being angle bisectors, fits a rhombus. A rhombus has 2 lines of symmetry (its diagonals), which bisect its angles. An isosceles trapezoid has 1 line of symmetry; a rectangle's 2 lines of symmetry are not angle bisectors (unless square, which has 4 lines); a square has 4 lines of symmetry. Thus, the rhombus statement is true.

Answer:

The figure could be a rhombus because the 2 lines of symmetry bisect the angles.