Question

quadrilateral vwxy is a rhombus. what is $m\angle xwy$?
$m\angle xwy = \square ^\circ$
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Explanation:

Step1: Use rhombus side property

In rhombus VWXY, $WX = XY$, so $\triangle WXY$ is isosceles.

Step2: Find base angles of $\triangle WXY$

The sum of angles in a triangle is $180^\circ$. Let $m\angle XWY = m\angle XYW = x$.
$$180^\circ - 58^\circ = 2x$$
$$122^\circ = 2x$$

Step3: Solve for $x$

$$x = \frac{122^\circ}{2}$$

Answer:

$61^\circ$