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Question
question 10 of 25
what value of ( b ) makes the trinomial below a perfect square?
( x^2 - bx + 16 )
a. 2
b. 4
c. 16
d. 8
Step1: Recall perfect square trinomial formula
A perfect square trinomial has the form \((x - a)^2 = x^2 - 2ax + a^2\). Comparing with \(x^2 - bx + 16\), we see that \(a^2 = 16\).
Step2: Solve for \(a\)
Taking the square root of both sides, \(a=\pm4\). But since the middle term is \(-bx\), we focus on the coefficient of \(x\). From the formula, the coefficient of \(x\) is \(-2a\), so \(-b=-2a\) or \(b = 2a\).
Step3: Find \(b\)
If \(a = 4\), then \(b=2\times4 = 8\). If \(a=- 4\), \(b = 2\times(-4)=-8\), but since we are looking at the options (positive values considered here as the options are positive), \(b = 8\).
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D. 8