Question

question 5 of 10
solve $3ax + 4ax = 5ax + 4$ for $x$ assume $a \
eq 0$.

a. $x = 3a$
b. $x = 2a$
c. $x = \frac{2}{a}$
d. $x = \frac{1}{3a}$

Explanation:

Step1: Combine like terms on left

$3ax + 4ax = 7ax$
Equation becomes: $7ax = 5ax + 4$

Step2: Subtract $5ax$ from both sides

$7ax - 5ax = 5ax + 4 - 5ax$
$2ax = 4$

Step3: Isolate $x$ (divide by $2a$)

$x = \frac{4}{2a} = \frac{2}{a}$

Answer:

C. $x = \frac{2}{a}$