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Question
question 3 of 10
what transformations were applied to ( abcd ) to obtain ( abcd )?
coordinate grid image with two squares (blue ( abcd ), red ( abcd ))
a. rotate 90 degrees counterclockwise about the origin, then translate 2 units down.
b. rotate 90 degrees counterclockwise about the origin, then translate 1 unit down.
To solve this, we analyze the transformation steps:
Step 1: Identify the Rotation
First, check the rotation. A 90° counterclockwise rotation about the origin transforms a point \((x, y)\) to \((-y, x)\). Let’s take a vertex of \(ABCD\) (e.g., \(A(2, 5)\)):
- After 90° counterclockwise rotation: \((-5, 2)\).
Step 2: Identify the Translation
Next, check the translation to match \(A'\). From the graph, \(A'\) is at \((-5, 4)\). The vertical change from \((-5, 2)\) to \((-5, 4)\) is \(4 - 2 = 2\) units down? Wait, no—wait, let’s recheck coordinates. Wait, original \(A\) is \((2, 5)\)? Wait, looking at the grid: \(A\) is at \((2, 5)\)? Wait, no, the blue square \(ABCD\): \(A\) is at \((2, 5)\)? Wait, no, the y-axis: \(A\) is at (2, 5)? Wait, the red square \(A'B'C'D'\): \(A'\) is at (-5, 4), \(B'\) at (-7, 4), etc. Wait, maybe I misread. Let's correct:
Original \(A\) (blue) is at \((2, 5)\)? No, wait, the grid: \(A\) is at (2, 5)? Wait, the y-coordinate for \(A\) is 5? Wait, the blue square: \(A\) is at (2, 5), \(B\) at (2, 8), \(C\) at (6, 8), \(D\) at (6, 5). Then rotating 90° counterclockwise: \((x, y) \to (-y, x)\). So \(A(2, 5)\) becomes \((-5, 2)\), \(B(2, 8)\) becomes \((-8, 2)\), \(C(6, 8)\) becomes \((-8, 6)\), \(D(6, 5)\) becomes \((-5, 6)\). Now, translating these points to \(A'(-5, 4)\), \(B'(-7, 4)\), \(C'(-7, 8)\), \(D'(-5, 8)\)? Wait, no, the red square: \(B'\) is at (-7, 4), \(A'\) at (-5, 4), \(D'\) at (-5, 8), \(C'\) at (-7, 8). Wait, the rotated points after 90° CCW: \(A(-5, 2)\), \(B(-8, 2)\), \(C(-8, 6)\), \(D(-5, 6)\). Then translating down by 2 units: \((-5, 2 - 2) = (-5, 0)\)? No, that’s not matching. Wait, maybe rotation is 90° clockwise? Wait, 90° clockwise rotation is \((x, y) \to (y, -x)\). Let's try \(A(2, 5)\): \((5, -2)\). No, that’s not. Wait, maybe the original \(A\) is (2, 5)? Wait, the y-axis: the blue square is on the right, red on the left. Let's list coordinates:
Blue \(ABCD\):
- \(A\): (2, 5)
- \(B\): (2, 8)
- \(C\): (6, 8)
- \(D\): (6, 5)
Red \(A'B'C'D'\):
- \(A'\): (-5, 4)
- \(B'\): (-7, 4)
- \(C'\): (-7, 8)
- \(D'\): (-5, 8)
Now, check rotation: 90° counterclockwise about origin: \((x, y) \to (-y, x)\). So \(A(2, 5) \to (-5, 2)\), \(B(2, 8) \to (-8, 2)\), \(C(6, 8) \to (-8, 6)\), \(D(6, 5) \to (-5, 6)\). Now, translate these points to match \(A'\), \(B'\), etc. The y-coordinate of \(A'\) is 4, which is \(2 - 2 = 0\)? No, wait \(A'\) is (-5, 4), rotated \(A\) is (-5, 2). So \(2 + 2 = 4\)? No, down? Wait, 2 to 4 is up? No, 2 to 4 is +2, but the direction: if we translate down 2 units, 2 - 2 = 0, which is wrong. Wait, maybe the rotation is 90° clockwise? 90° clockwise: \((x, y) \to (y, -x)\). \(A(2, 5) \to (5, -2)\), no. Wait, maybe the original \(A\) is (2, 5)? Wait, maybe I made a mistake. Let's check the answer options. Option A: Rotate 90° CCW about origin, then translate 2 units down. Let's test with \(A(2, 5)\):
- Rotate 90° CCW: \((-5, 2)\)
- Translate 2 units down: \((-5, 2 - 2) = (-5, 0)\) → not \(A'(-5, 4)\). Wait, maybe the original \(A\) is (2, 6)? Wait, the grid lines: each grid is 1 unit. Let's re-express coordinates:
Blue square:
- \(A\): (2, 5) (y=5, x=2)
- \(B\): (2, 8) (y=8, x=2)
- \(C\): (6, 8) (y=8, x=6)
- \(D\): (6, 5) (y=5, x=6)
Red square:
- \(A'\): (-5, 4) (y=4, x=-5)
- \(B'\): (-7, 4) (y=4, x=-7)
- \(C'\): (-7, 8) (y=8, x=-7)
- \(D'\): (-5, 8) (y=8, x=-5)
Wait, the red square’s \(A'\) and \(B'\) have y=4, \(C'\) and \(D'\) have y=8. The blue square’s \(A\) and \(D\) have y=5, \(B\) and \(C\) have y=8. So the vertical translation: from y=5 (blue \(A\)) to y…
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A. Rotate 90 degrees counterclockwise about the origin, then translate 2 units down.