Question

question 11 of 20 which conic section does the equation below describe?
\\(\frac{(x - 1)^2}{20}-\frac{(y + 2)^2}{16}=1\\)
a. parabola
b. circle
c. ellipse
d. hyperbola

Explanation:

The general form of a hyperbola is $\frac{(x - h)^2}{a^2}-\frac{(y - k)^2}{b^2}=1$ or $\frac{(y - k)^2}{a^2}-\frac{(x - h)^2}{b^2}=1$. The given equation $\frac{(x - 1)^2}{20}-\frac{(y + 2)^2}{16}=1$ is in the form of a hyperbola with center $(h,k)=(1,-2)$, $a^2 = 20$, $b^2=16$.

Answer:

D. Hyperbola