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Question
question 15 of 25 what is the approximate value of sin b? a. 2.29 b. 0.92 c. 0.40 d. 1.09
Step1: Recall sine - definition
In a right - triangle, $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$. For $\angle B$, the side opposite to $\angle B$ is $AC = 16$ and the hypotenuse is $BC=17.46$.
Step2: Calculate $\sin B$
$\sin B=\frac{AC}{BC}=\frac{16}{17.46}\approx0.92$. However, we made a mistake above. For $\angle B$, the side opposite to $\angle B$ is $AC$, but we should use the side adjacent to $\angle B$ (which is $AB = 7$) and the hypotenuse $BC = 17.46$. So $\sin B=\frac{AB}{BC}=\frac{7}{17.46}\approx0.40$.
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C. 0.40