Question

question 2 20 pts solve -40 + 16 ≤ 3m + 6. o m ≥ -6 o m ≥ -10 o m ≤ -10 o m ≤ -6

Explanation:

Step1: Simplify the left - hand side

First, simplify $-40 + 16$ which is $-24$. So the inequality becomes $-24\leq3m + 6$.

Step2: Isolate the term with $m$

Subtract 6 from both sides of the inequality: $-24-6\leq3m+6 - 6$. This simplifies to $-30\leq3m$.

Step3: Solve for $m$

Divide both sides of the inequality by 3: $\frac{-30}{3}\leq\frac{3m}{3}$. So $m\geq - 10$.

Answer:

$m\geq - 10$