Question

question 2select the correct answer.what is the solution to this system of equations?$x + y + z = 2LXB0x - 4y + 2z = 6LXB1circ$ infinite solutions$circ$ $(2,0,2)$$circ$ no solutions

Explanation:

Step1: Simplify the second equation

Take the second equation $2x + 2y + 2z = 1$, factor out 2 from the left side:
$2(x + y + z) = 1$
Divide both sides by 2:
$x + y + z = \frac{1}{2}$

Step2: Compare with first equation

The first equation is $x + y + z = 2$. Now we have two contradictory statements: $x + y + z = 2$ and $x + y + z = \frac{1}{2}$. A system of equations with contradictory equations has no solutions.

Answer:

no solutions