Question

question
in △def, the measure of ∠f = 90°, ed = 53, df = 45, and fe = 28. what ratio represents the sine of ∠d?
answer attempt 1 out of 5

Explanation:

Step1: Recall sine definition for right triangles

For an acute angle in a right triangle, $\sin(\theta) = \frac{\text{opposite side}}{\text{hypotenuse}}$

Step2: Identify sides for $\angle D$

In $\triangle DEF$ with $\angle F=90^\circ$, opposite side to $\angle D$ is $FE=28$, hypotenuse is $ED=53$.

Step3: Write the sine ratio

$\sin(\angle D) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{FE}{ED}$

Answer:

$\frac{28}{53}$