Question

question 6
evaluate \\( \lim_{x \to \infty} \frac{6x^2 - 8x + 12}{13x^3 - 5x^2 - 9x - 27} \\)
\\( \bigcirc \\) infinity
\\( \bigcirc \\) 0
\\( \bigcirc \\) 6/13
\\( \bigcirc \\) - infinity

Explanation:

Step1: Identify degrees of numerator/denominator

Numerator degree: $2$, Denominator degree: $3$

Step2: Apply limit rule for rational functions

For $\lim_{x \to \infty} \frac{P(x)}{Q(x)}$, if $\deg(P) < \deg(Q)$, limit = $0$

Answer:

0