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Question
question
evaluate the limit:
$lim_{x
ightarrow13}\frac{sqrt{x - 12}-10}{x - 3}$
Step1: Substitute $x = 13$
$\lim_{x
ightarrow13}\frac{\sqrt{x - 12}-10}{x - 3}=\frac{\sqrt{13 - 12}-10}{13 - 3}$
Step2: Simplify numerator and denominator
$\frac{\sqrt{1}-10}{10}=\frac{1 - 10}{10}$
Step3: Calculate the result
$\frac{1 - 10}{10}=-\frac{9}{10}$
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$\frac{\sqrt{13 - 12}-10}{13 - 3}=\frac{1 - 10}{10}=-\frac{9}{10}$