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Question
question
factor.
$x^2 - 7x - 18$
Step1: Find two numbers
We need two numbers that multiply to \(-18\) and add up to \(-7\). Let's list the factor pairs of \(-18\): \((-9, 2)\) because \(-9\times2 = -18\) and \(-9 + 2=-7\).
Step2: Factor the quadratic
Using the numbers we found, we can factor \(x^{2}-7x - 18\) as \((x - 9)(x + 2)\). Because when we expand \((x - 9)(x + 2)\) using the distributive property (FOIL method), we get \(x^{2}+2x-9x - 18=x^{2}-7x - 18\), which matches the original quadratic.
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\((x - 9)(x + 2)\)