Question

question 9
find the equation of a line containing the following points. write the equation in slope - intercept form.
(-1, -3) and (-3, 2)
y =
question help: video written example post to forum
submit

Explanation:

Step1: Calculate the slope

The slope formula is $m=\frac{y_2-y_1}{x_2-x_1}$. Using points $(-1,-3)$ and $(-3,2)$:
$m=\frac{2-(-3)}{-3-(-1)}=\frac{5}{-2}=-\frac{5}{2}$

Step2: Find y-intercept $b$

Use slope-intercept form $y=mx+b$, substitute $m=-\frac{5}{2}$ and point $(-1,-3)$:
$-3 = -\frac{5}{2}(-1) + b$
$-3 = \frac{5}{2} + b$
$b = -3 - \frac{5}{2} = -\frac{6}{2} - \frac{5}{2} = -\frac{11}{2}$

Step3: Write final equation

Substitute $m$ and $b$ into $y=mx+b$.

Answer:

$y=-\frac{5}{2}x-\frac{11}{2}$