Question

question
find the quotient of $-8s^5 - 2s^4 - 14s^3 + 4s^2$ divided by $2s^2$.

Explanation:

Step1: Divide each term by \(2s^2\)

For the first term: \(\frac{-8s^5}{2s^2} = -4s^{5 - 2} = -4s^3\)
For the second term: \(\frac{-2s^4}{2s^2} = -s^{4 - 2} = -s^2\)
For the third term: \(\frac{-14s^3}{2s^2} = -7s^{3 - 2} = -7s\)
For the fourth term: \(\frac{4s^2}{2s^2} = 2\)

Step2: Combine the results

Combine the terms we got from each division: \(-4s^3 - s^2 - 7s + 2\)

Answer:

\(-4s^3 - s^2 - 7s + 2\)