Question

question 3
given the function
$f(x) = \

$$\begin{cases}8x + 5 & x < 0 \\\\ 8x + 10 & x \\geq 0 \\end{cases}$$

$
calculate the following values:
$f(-1) = \square$
$f(0) = \square$
$f(2) = \square$
question help: video

Explanation:

Step1: Calculate \( f(-1) \)

Since \( -1 < 0 \), we use the first part of the piecewise function \( f(x) = 8x + 5 \). Substitute \( x = -1 \) into this function:
\( f(-1) = 8(-1) + 5 = -8 + 5 = -3 \)

Step2: Calculate \( f(0) \)

Since \( 0 \geq 0 \), we use the second part of the piecewise function \( f(x) = 8x + 10 \). Substitute \( x = 0 \) into this function:
\( f(0) = 8(0) + 10 = 0 + 10 = 10 \)

Step3: Calculate \( f(2) \)

Since \( 2 \geq 0 \), we use the second part of the piecewise function \( f(x) = 8x + 10 \). Substitute \( x = 2 \) into this function:
\( f(2) = 8(2) + 10 = 16 + 10 = 26 \)

Answer:

\( f(-1) = -3 \)
\( f(0) = 10 \)
\( f(2) = 26 \)