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Question
question 6 (multiple choice worth 1 points)(05.01r mc)solve $8 = 2^{x + 4}$.$x = -4$$x = -1$$x = 0$$x = 7$
Step1: Rewrite 8 as power of 2
$8 = 2^3$, so the equation becomes:
$2^3 = 2^{x+4}$
Step2: Set exponents equal
Since bases are equal, exponents are equal:
$3 = x + 4$
Step3: Solve for x
Subtract 4 from both sides:
$x = 3 - 4$
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x = -1