Question

question
perform the operation.
(2x^{2}-4)-(-x^{2}+3x - 6)

Explanation:

Step1: Remove parentheses

When we have $-( -x^{2}+3x - 6)$, we distribute the negative sign. So, $(2x^{2}-4)-(-x^{2}+3x - 6)=2x^{2}-4 + x^{2}-3x + 6$.

Step2: Combine like - terms

Combine the $x^{2}$ terms: $2x^{2}+x^{2}=3x^{2}$, and combine the constant terms: $-4 + 6 = 2$. The $-3x$ term remains as it is. So the result is $3x^{2}-3x + 2$.

Answer:

$3x^{2}-3x + 2$