Question

question
perform the operation.
$(-8x^2 + 3) + (x^2 + 3x - 8)$

Explanation:

Step1: Remove parentheses

$(-8x^{2}+3)+(x^{2}+3x - 8)=-8x^{2}+3+x^{2}+3x - 8$

Step2: Combine like terms

For $x^{2}$ terms: $-8x^{2}+x^{2}=-7x^{2}$
For constant terms: $3 - 8=-5$
The $3x$ term remains as it is.
So the result is $-7x^{2}+3x - 5$

Answer:

$-7x^{2}+3x - 5$