Question

question 1
0/1 pt 3 99 deta
simplify the rational expression.
$\frac{y^{2}-4}{y^{2}+3y+2} = square$
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question 2
0/1 pt 3 99 det
simplify the rational expression.
$\frac{25a^{2}-10a+1}{5a-1} = square$
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submit

Explanation:

Question 1

Step1: Factor numerator (difference of squares)

$y^2 - 4 = (y-2)(y+2)$

Step2: Factor denominator (quadratic)

$y^2 + 3y + 2 = (y+1)(y+2)$

Step3: Cancel common factor $(y+2)$

$\frac{(y-2)(y+2)}{(y+1)(y+2)} = \frac{y-2}{y+1}$ (where $y
eq -2, -1$)

Question 2

Step1: Factor numerator (perfect square trinomial)

$25a^2 -10a +1 = (5a-1)^2$

Step2: Cancel common factor $(5a-1)$

$\frac{(5a-1)^2}{5a-1} = 5a-1$ (where $a
eq \frac{1}{5}$)

Answer:

1. $\frac{y-2}{y+1}$
2. $5a-1$