Question

question 4
4.5 pts
solve for x.
$3\sqrt{x}=6$
$x=$

question 5
6 pts
solve for x
$-6\sqrt{3x-4}+1=-11$
$x=$

Explanation:

Step1: Isolate the square root term (Q4)

Divide both sides by 3:
$$\frac{3\sqrt{x}}{3} = \frac{6}{3}$$
$$\sqrt{x} = 2$$

Step2: Eliminate the square root (Q4)

Square both sides:
$$(\sqrt{x})^2 = 2^2$$
$$x = 4$$

Step3: Isolate the square root term (Q5)

Subtract 1 from both sides, then divide by -6:
$$-6\sqrt{3x-4} = -11 - 1$$
$$-6\sqrt{3x-4} = -12$$
$$\sqrt{3x-4} = \frac{-12}{-6} = 2$$

Step4: Eliminate the square root (Q5)

Square both sides, then solve for x:
$$(\sqrt{3x-4})^2 = 2^2$$
$$3x - 4 = 4$$
$$3x = 4 + 4 = 8$$
$$x = \frac{8}{3}$$

Answer:

Question 4: $4$
Question 5: $\frac{8}{3}$