Question

question 5 of 5 select the correct answer. factor the polynomial below. $x^{2}+15x + 56$ (x + 56)(x + 1) (x + 8)(x + 7) (x - 8)(x + 7) (x - 8)(x - 7)

Explanation:

Step1: Recall factoring formula

For a quadratic polynomial $x^{2}+bx + c$, we need to find two numbers $m$ and $n$ such that $m + n=b$ and $m\times n = c$. Here $b = 15$ and $c=56$.

Step2: Find two numbers

We need to find two numbers that add up to 15 and multiply to 56. The numbers 8 and 7 satisfy $8 + 7=15$ and $8\times7 = 56$.

Step3: Write factored form

The factored form of $x^{2}+15x + 56$ is $(x + 8)(x + 7)$.

Answer:

B. $(x + 8)(x + 7)$