Question

question
simplify \\(\frac{0!}{4!3!}\\) without any factorials.

answer attempt 1 out of 2

Explanation:

Step1: Recall the definition of factorial

We know that \(0! = 1\), \(n!=n\times(n - 1)\times\cdots\times1\) for \(n\geq1\). So \(4!=4\times3\times2\times1 = 24\) and \(3!=3\times2\times1=6\).

Step2: Substitute the factorial values into the expression

Substitute \(0! = 1\), \(4! = 24\) and \(3! = 6\) into \(\frac{0!}{4!3!}\), we get \(\frac{1}{24\times6}\).

Step3: Calculate the denominator

Calculate \(24\times6=144\), so the expression becomes \(\frac{1}{144}\).

Answer:

\(\frac{1}{144}\)