Question

question 8
solve for x.
$sqrt{x + 8} = sqrt{3x + 10}$

question 9
1 pts
this is an example of an sat/tsi questions. no graphing allowed.
if $sqrt{10x + z} = sqrt{3x - 49}$, find the solution if the value of z = 7.
$x=1$
$x=5$
$x=-2$
$x=-6$

Explanation:

Question 8

Step1: Square both sides

$$(\sqrt{x+8})^2 = (\sqrt{3x+10})^2$$
$$x + 8 = 3x + 10$$

Step2: Isolate x terms

$$8 - 10 = 3x - x$$
$$-2 = 2x$$

Step3: Solve for x

$$x = \frac{-2}{2}$$

Step1: Substitute z=7

$$\sqrt{10x + 7} = \sqrt{3x - 49}$$

Step2: Square both sides

$$10x + 7 = 3x - 49$$

Step3: Isolate x terms

$$10x - 3x = -49 - 7$$
$$7x = -56$$

Step4: Solve for x

$$x = \frac{-56}{7}$$

Answer:

$x = -1$

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Question 9