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question suppose we have a function defined by f(x)=\begin{cases}2&\tex…

Question

question
suppose we have a function defined by
f(x)=\begin{cases}2&\text{for }x > 1,\\x&\text{for }0 < xleq1,\\ - 1&\text{for }xleq0.end{cases}
what is the value of (f(0))?
provide your answer below:

Explanation:

Step1: Identify the condition for x = 0

We are looking for f(0). Since 0 ≤ 0, we use the third - part of the piece - wise function.

Step2: Determine the function value

The third part of the function is f(x)= - 1 for x ≤ 0. Substituting x = 0 into this part, we get f(0)= - 1.

Answer:

-1