Question

question 8
what is the vertex of the function, f(x) = 2x² - 3x + 1?
(0.5, 0)
(0.75, -0.125)
(0, 1)
(1,0)

Explanation:

Step1: Find x-coordinate of vertex

For quadratic $f(x)=ax^2+bx+c$, $x = -\frac{b}{2a}$.
Here $a=2$, $b=-3$, so $x = -\frac{-3}{2\times2} = \frac{3}{4} = 0.75$

Step2: Find y-coordinate of vertex

Substitute $x=0.75$ into $f(x)$.
$f(0.75)=2(0.75)^2 - 3(0.75) + 1 = 2(0.5625) - 2.25 + 1 = 1.125 - 2.25 + 1 = -0.125$

Answer:

(0.75, -0.125)