Question

the quotient of $21x^3 - 21x^2 - 9x$ divided by $-3x$.

Explanation:

Step1: Split the polynomial into terms

$\frac{21x^3 - 21x^2 - 9x}{-3x} = \frac{21x^3}{-3x} + \frac{-21x^2}{-3x} + \frac{-9x}{-3x}$

Step2: Simplify each fraction

$\frac{21x^3}{-3x} = -7x^2$, $\frac{-21x^2}{-3x} = 7x$, $\frac{-9x}{-3x} = 3$

Step3: Combine simplified terms

$-7x^2 + 7x + 3$

Answer:

$-7x^2 + 7x + 3$