QUESTION IMAGE
Question
s represent positive real numbers).
- \\(\sqrt{150}\\)
- \\(\sqrt3{16}\\)
- \\(\sqrt4{32}\\)
- \\(\sqrt5{128}\\)
- \\(\sqrt3{\frac{32}{125}}\\)
- \\(-\sqrt3{8k^9}\\)
- \\(-\sqrt3{-125m^9}\\)
- \\(\sqrt{75y^3}\\)
- \\(\sqrt3{8z^9r^{12}}\\)
- \\(\sqrt4{16a^8b^{12}}\\)
Step1: Simplify $\sqrt{150}$
Factor 150 into perfect square: $150=25\times6$
$\sqrt{150}=\sqrt{25\times6}=\sqrt{25}\times\sqrt{6}=5\sqrt{6}$
Step2: Simplify $\sqrt[3]{16}$
Factor 16 into perfect cube: $16=8\times2$
$\sqrt[3]{16}=\sqrt[3]{8\times2}=\sqrt[3]{8}\times\sqrt[3]{2}=2\sqrt[3]{2}$
Step3: Simplify $\sqrt[4]{32}$
Factor 32 into perfect 4th power: $32=16\times2$
$\sqrt[4]{32}=\sqrt[4]{16\times2}=\sqrt[4]{16}\times\sqrt[4]{2}=2\sqrt[4]{2}$
Step4: Simplify $\sqrt[5]{128}$
Factor 128 into perfect 5th power: $128=32\times4$
$\sqrt[5]{128}=\sqrt[5]{32\times4}=\sqrt[5]{32}\times\sqrt[5]{4}=2\sqrt[5]{4}$
Step5: Simplify $\sqrt[3]{\frac{32}{125}}$
Split root, factor numerator: $\sqrt[3]{\frac{32}{125}}=\frac{\sqrt[3]{32}}{\sqrt[3]{125}}=\frac{\sqrt[3]{8\times4}}{5}=\frac{2\sqrt[3]{4}}{5}$
Step6: Simplify $-\sqrt[3]{8k^9}$
Factor term inside root: $8k^9=8(k^3)^3$
$-\sqrt[3]{8k^9}=-\sqrt[3]{8}\times\sqrt[3]{(k^3)^3}=-2k^3$
Step7: Simplify $-\sqrt[3]{-125m^9}$ (assuming missing term is $m^9$)
Negative inside cube root: $-\sqrt[3]{-125m^9}=-(-\sqrt[3]{125m^9})=\sqrt[3]{125}\times\sqrt[3]{(m^3)^3}=5m^3$
Step8: Simplify $\sqrt{75y^3}$
Factor into perfect square: $75y^3=25y^2\times3y$
$\sqrt{75y^3}=\sqrt{25y^2}\times\sqrt{3y}=5y\sqrt{3y}$
Step9: Simplify $\sqrt[3]{8z^9r^{12}}$
Factor into perfect cube: $8z^9r^{12}=8(z^3)^3(r^4)^3$
$\sqrt[3]{8z^9r^{12}}=\sqrt[3]{8}\times\sqrt[3]{(z^3)^3}\times\sqrt[3]{(r^4)^3}=2z^3r^4$
Step10: Simplify $\sqrt[4]{16a^8b^{12}}$
Factor into perfect 4th power: $16a^8b^{12}=16(a^2)^4(b^3)^4$
$\sqrt[4]{16a^8b^{12}}=\sqrt[4]{16}\times\sqrt[4]{(a^2)^4}\times\sqrt[4]{(b^3)^4}=2a^2b^3$
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