Question

rewrite in exponential form: $log_{4}\frac{1}{64} = -3LXB04^{\frac{1}{64}} = -3LXB14^{-3}=\frac{1}{64}$

Explanation:

Step1: Recall log-exponential conversion

For $\log_b a = c$, exponential form is $b^c = a$

Step2: Match values to the rule

Here, $b=4$, $a=\frac{1}{64}$, $c=-3$
Substitute into the exponential form: $4^{-3} = \frac{1}{64}$

Answer:

$4^{-3} = \frac{1}{64}$ (the option in the blue box on the far right)