Question

rewrite using a single positive exponent.\\(\frac{7^{8}}{7^{3}}\\)

Explanation:

Step1: Apply quotient of powers rule

For same bases, subtract exponents: $\frac{a^m}{a^n}=a^{m-n}$
$\frac{7^8}{7^3}=7^{8-3}$

Step2: Calculate exponent difference

Subtract the exponents: $8-3=5$
$7^{8-3}=7^5$

Answer:

$7^5$