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a room has dimensions of 10.0 ft × 20.0 ft × 8.00 ft. given that there …

Question

a room has dimensions of 10.0 ft × 20.0 ft × 8.00 ft. given that there are three feet in a yard, what is the volume of the room in yd³? 59.3 1.60×10³ 178 533 none of the above

Explanation:

Step1: Calculate volume in cubic - feet

The volume $V$ of a rectangular - shaped room with length $l = 20.0$ ft, width $w = 10.0$ ft, and height $h = 8.00$ ft is given by the formula $V=l\times w\times h$.
$V = 20.0\times10.0\times8.00=1600$ ft³

Step2: Convert cubic - feet to cubic - yards

Since 1 yard = 3 feet, then 1 yd³=(3 ft)×(3 ft)×(3 ft)=27 ft³.
To convert the volume from cubic - feet to cubic - yards, we divide the volume in cubic - feet by 27.
$V_{yd^3}=\frac{1600}{27}\approx59.3$ yd³

Answer:

59.3