Question

row a in a certain section in a football stadium has 10 seats. each row behind row a (and so on) has 6 more seats than the row immediately in front of it. how many seats are in row g of this section of the stadium? there are a seats in row g.

Explanation:

Step1: Identify the arithmetic - sequence formula

The formula for the $n$th term of an arithmetic sequence is $a_n=a_1+(n - 1)d$, where $a_1$ is the first - term, $n$ is the term number, and $d$ is the common difference.

Step2: Determine the values of $a_1$, $n$, and $d$

Here, row A is considered the first row, so $a_1 = 10$. The rows are A, B, C, D, E, F, G. So for row G, $n=7$ (since A is the 1st row, B is the 2nd row, and so on). The common difference $d = 6$ (as each row has 6 more seats than the previous row).

Step3: Substitute the values into the formula

Substitute $a_1 = 10$, $n = 7$, and $d = 6$ into the formula $a_n=a_1+(n - 1)d$. We get $a_7=10+(7 - 1)\times6$.

Step4: Calculate the result

First, calculate $(7 - 1)\times6=6\times6 = 36$. Then, $a_7=10 + 36=46$.

Answer:

46