Question

sample response: you would graph the equation $f(x) = -x + 3$ for input values less than 2. there would be an open circle at the point $(2, 1)$ since the domain for the first piece does not include 2. you would then graph a horizontal line at $f(x) = 3$ for input values between 2 and 4. there would be a closed circle at $(2, 3)$ and an open circle at $(4, 3)$. last, you would graph $f(x) = 4 - 2x$ for input values greater than or equal to 4. there would be a closed circle at the point $(4, -4)$ since 4 is in the domain of the third piece.
what did you include in your response? check all that apply.
$square$ there would be an open circle at $(2, 1)$.
$square$ there would be a closed circle at $(2, 3)$.
$square$ there would be an open circle at $(4, 3)$.
$square$ there would be a closed circle at $(4, -4)$.

Explanation:

All the listed circle points are explicitly mentioned in the provided sample response as part of the piecewise function graphing instructions.

Answer:

• There would be an open circle at (2, 1).
• There would be a closed circle at (2, 3).
• There would be an open circle at (4, 3).
• There would be a closed circle at (4, -4).