Question

the segment below is dilated by a scale factor of 2 to form $overline{uv}$. what is the measure of $uv$? answer attempt 1 out of 999

Explanation:

Step1: Recall dilation formula

When a segment is dilated, the length of the new segment $U'V'$ is the original length times the scale - factor. Let the original length of $\overline{UV}$ be $l = 48$ and the scale - factor be $k = 2$.
The formula for the length of the dilated segment is $l'=k\times l$.

Step2: Calculate the length of $U'V'$

Substitute $k = 2$ and $l = 48$ into the formula: $U'V'=2\times48$.
$U'V' = 96$.

Answer:

96