Question

1. select all of the inequalities that have the value $u = -3$ as a solution.

$11 - 2u \leq 15$
$\frac{u}{3} + 8 \geq 10$
$4u - 9 \leq -5$
$-5u - 6 \geq 4$
submit

Explanation:

Step1: Substitute $u=-3$ into first inequality

$11 - 2(-3) = 11 + 6 = 17$. Check $17 \leq 15$? No.

Step2: Substitute $u=-3$ into second inequality

$\frac{-3}{3} + 8 = -1 + 8 = 7$. Check $7 \geq 10$? No.

Step3: Substitute $u=-3$ into third inequality

$4(-3) - 9 = -12 - 9 = -21$. Check $-21 \leq -5$? Yes.

Step4: Substitute $u=-3$ into fourth inequality

$-5(-3) - 6 = 15 - 6 = 9$. Check $9 \geq 4$? Yes.

Answer:

$4u - 9 \leq -5$, $-5u - 6 \geq 4$