Question

select the correct answer. an animal reservation has four different regions for animals. the number of animals in each region is shown in the table. which region has a population density less than 60 animals per square mile? region number of animals sketch of region a 42,500 35 mi 40 mi b 60,800 50 mi 38 mi c 57,300 49 mi 42 mi d 49,200 32 mi 51 mi

Explanation:

Step1: Recall the formula for the area of a triangle

$A=\frac{1}{2}\times base\times height$

Step2: Calculate the area of region A

$A_A=\frac{1}{2}\times35\times40 = 700$ square - miles. Then the population - density of region A is $\frac{42500}{700}\approx60.71$ animals per square - mile.

Step3: Calculate the area of region B

$A_B=\frac{1}{2}\times38\times50 = 950$ square - miles. Then the population - density of region B is $\frac{60800}{950}=64$ animals per square - mile.

Step4: Calculate the area of region C

$A_C=\frac{1}{2}\times42\times49 = 1029$ square - miles. Then the population - density of region C is $\frac{57300}{1029}\approx55.68$ animals per square - mile.

Step5: Calculate the area of region D

$A_D=\frac{1}{2}\times51\times32 = 816$ square - miles. Then the population - density of region D is $\frac{49200}{816}\approx60.3$ animals per square - mile.

Answer:

C