Question

select the correct answer from each drop - down menu.
if a heterozygous trait with the genotype ww is mated with a homozygous recessive female of genotype ww. there is a chance that
of the offspring will be heterozygous.

	w	w
w	ww	ww

if one heterozygous, ww is crossed with a homozygous dominant, ww, then the probability of having a homozygous recessive offspring is

	w	w
w	ww	ww

Explanation:

Step1: Analyze first cross (Ww x ww)

The Punnett square gives genotypes: Ww, ww, Ww, ww. Count heterozygous (Ww) offspring: 2 out of 4.
Probability: $\frac{2}{4} = \frac{1}{2}$

Step2: Analyze second cross (Ww x WW)

The Punnett square gives genotypes: WW, Ww, WW, Ww. Count homozygous recessive (ww) offspring: 0 out of 4.
Probability: $\frac{0}{4} = 0$

Answer:

1. For the cross of heterozygous (Ww) and homozygous recessive (ww): $\frac{1}{2}$ (or 50%) of the offspring will be heterozygous.
2. For the cross of heterozygous (Ww) and homozygous dominant (WW): 0 (or 0%) probability of having a homozygous recessive offspring.