Question

select the fully reduced form of this fraction.\\(\frac{40x}{-15}\\)\
a. \\(-\frac{3x}{8}\\)\
\\(\quad\\) b. \\(25x\\)\
\\(\quad\\) c. \\(-\frac{8x}{3}\\)\
d. \\(\frac{8x}{3}\\)\
\\(\quad\\) e. already fully reduced

Explanation:

Step1: Find GCD of 40 and 15

GCD(40,15) = 5

Step2: Divide numerator and denominator by GCD

$\frac{40x \div 5}{-15 \div 5} = \frac{8x}{-3} = -\frac{8x}{3}$

Answer:

C. $-\frac{8x}{3}$