Question

select a setting so that each given point will lie within the viewing window. (0,0), (120,15), (5,100) xmin = - 10 xmax = 130 xscl = 10 ymin = - 10 ymax = 110 yscl = 10 xmin = - 10 xmax = 130 xscl = 10 ymin = 10 ymax = 110 yscl = 10 xmin = 10 xmax = 110 xscl = 10 ymin = - 10 ymax = 130 yscl = 10 xmin = - 10 xmax = 110 xscl = 10 ymin = - 10 ymax = 130 yscl = 10

Explanation:

Step1: Analyze x - coordinates

The x - coordinates of the points are 0, 120, 5. The minimum x - value among them is 0 and the maximum is 120. We need \(X_{min}\leq0\) and \(X_{max}\geq120\).

Step2: Analyze y - coordinates

The y - coordinates of the points are 0, 15, 100. The minimum y - value is 0 and the maximum is 100. We need \(Y_{min}\leq0\) and \(Y_{max}\geq100\).

Step3: Check options

For the first option: \(X_{min}=- 10\), \(X_{max}=130\), \(Y_{min}=-10\), \(Y_{max}=110\), \(X_{scl}=10\), \(Y_{scl}=10\). The x - values 0, 120, 5 and y - values 0, 15, 100 all lie within this viewing - window.
For the second option: \(X_{min}=-10\), \(X_{max}=130\), \(Y_{min}=10\), \(Y_{max}=110\). Since \(Y_{min} = 10\), the point \((0,0)\) will not lie within the viewing - window.
For the third option: \(X_{min}=10\), \(X_{max}=110\). Since \(X_{min}=10\), the points \((0,0)\) and \((5,100)\) will not lie within the viewing - window.
For the fourth option: \(X_{min}=-10\), \(X_{max}=110\). Since \(X_{max}=110\), the point \((120,15)\) will not lie within the viewing - window.

Answer:

The first option with \(X_{min}=-10\), \(X_{max}=130\), \(Y_{min}=-10\), \(Y_{max}=110\), \(X_{scl}=10\), \(Y_{scl}=10\)