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show that the measure of an exterior angle is always equal to the sum o…

Question

show that the measure of an exterior angle is always equal to the sum of the measures of its non - adjacent interior angles. use the figure below to help.

Explanation:

Step1: Recall angle - sum property of a triangle

The sum of the interior angles of a triangle is 180°. In triangle with angles 1, 2, 3, we have $\angle1+\angle2+\angle3 = 180^{\circ}$.

Step2: Consider the linear - pair property

$\angle3$ and $\angle4$ form a linear - pair. So, $\angle3+\angle4=180^{\circ}$.

Step3: Equate the two expressions

Since $\angle1+\angle2+\angle3 = 180^{\circ}$ and $\angle3+\angle4 = 180^{\circ}$, we can set them equal to each other: $\angle1+\angle2+\angle3=\angle3+\angle4$.

Step4: Solve for $\angle4$

Subtract $\angle3$ from both sides of the equation $\angle1+\angle2+\angle3=\angle3+\angle4$. We get $\angle4=\angle1+\angle2$.

Answer:

We have shown that the measure of an exterior angle ($\angle4$) is equal to the sum of the measures of its non - adjacent interior angles ($\angle1$ and $\angle2$).