Question

this shows a function.
$f(x)=\

$$\begin{cases}8&;x < -6\\\\5x - x^{3};&x \\geq -6\\end{cases}$$

$
what is the value of $f(-1)$?

Explanation:

Step1: Check input range

$-1 \geq -6$, use $5x - x^3$

Step2: Substitute $x=-1$

$5(-1) - (-1)^3 = -5 - (-1)$

Step3: Calculate final value

$-5 + 1 = 4$

Answer:

4