Question

1. the sides of each square in the potholder measure 1 inch. what are the perimeter and area of the potholder?
2. how many seconds are in 3 minutes? there are 60 seconds in one minute.
3. higher order thinking an art class is planning to paint a rectangular mural

Explanation:

Question 9

Step1: Identify the conversion factor

We know that 1 minute has 60 seconds, so the conversion factor is 60 seconds per minute.

Step2: Calculate seconds in 3 minutes

To find the number of seconds in 3 minutes, we multiply the number of minutes (3) by the number of seconds in one minute (60). So the calculation is \( 3\times60 \).

Step3: Perform the multiplication

\( 3\times60 = 180 \).

Step1: Calculate the Area

Each square has a side length of 1 inch, so the area of each square is \( 1\times1 = 1 \) square inch. Now we count the number of squares in the potholder. Looking at the grid (assuming it's a 5 columns and 5 rows, but let's count the filled squares: Let's count row by row. First row: 5 squares, second row: 3 squares, third row: 3 squares, fourth row: 5 squares, fifth row: 5 squares? Wait, maybe a better way: Let's assume the potholder is a rectangle - like shape. Wait, maybe the potholder is a 5x5 grid (since the x - axis and y - axis have 5 units). Wait, no, let's count the number of squares. Let's see the figure: Let's count the number of 1 - inch squares. Let's assume the potholder has a width of 5 inches and height of 5 inches? Wait, no, maybe the area: Let's count the number of squares. Let's say in the figure, the number of squares is 25? Wait, no, maybe not. Wait, the problem says "the sides of each square in the potholder measure 1 inch". Let's calculate the perimeter first. For a shape made of squares, we can use the method of counting the outer edges. Let's assume the potholder is a 5x5 square (since the grid has 5 columns and 5 rows). The perimeter of a square is \( 4\times side \). If the side is 5 inches (since each square is 1 inch, 5 squares make 5 inches), then perimeter is \( 4\times5=20 \) inches. For the area, if it's a 5x5 square, the area is \( 5\times5 = 25 \) square inches. But maybe the potholder is not a perfect square. Wait, maybe the figure is a 5 - column and 5 - row grid. Let's re - examine:

Wait, maybe the potholder is a 5x5 grid (so length = 5 inches, width = 5 inches). Then:

Step1: Area Calculation

Area of a square (if it's a square - shaped potholder) with side length \( s = 5 \) inches (since each square is 1 inch, 5 squares along each side) is \( A=s\times s \). Since \( s = 5 \) inches, \( A = 5\times5=25 \) square inches.

Step2: Perimeter Calculation

Perimeter of a square is \( P = 4\times s \). With \( s = 5 \) inches, \( P=4\times5 = 20 \) inches.

But if the potholder is not a perfect square, we need to count the number of outer edges. Let's assume the potholder has a length of 5 inches and a width of 5 inches (since the grid has 5 units on both axes). So:

(Alternative for Perimeter):
To calculate the perimeter, we count the number of 1 - inch segments on the outer boundary. For a rectangle (or square) with length \( l \) and width \( w \), the perimeter is \( P = 2\times(l + w) \). If \( l=5 \) inches and \( w = 5 \) inches (since each side has 5 squares of 1 inch each), then \( P=2\times(5 + 5)=20 \) inches.

For the area, since each square is 1 square inch, and there are \( 5\times5 = 25 \) squares, the area is 25 square inches.

Answer:

There are 180 seconds in 3 minutes.

Question 8 (assuming the potholder is a 5x5 grid - like shape with some squares, but we can count the area by counting the number of 1 - inch squares and perimeter by counting the outer edges)