Question

simplify.\\(
\frac{7(2v + 3)(v - 8)}{28(2v + 3)(v - 8)}
\\)you may leave the numerator and denominator of your answer in factore

Explanation:

Step1: Cancel common binomial factors

Cancel $(2v+3)$ and $(v-8)$ from numerator and denominator (where $2v+3
eq0$ and $v-8
eq0$):
$\frac{7}{28}$

Step2: Simplify the numerical fraction

Divide numerator and denominator by their GCD (7):
$\frac{7\div7}{28\div7}=\frac{1}{4}$

Answer:

$\frac{1}{4}$ (with restrictions $v
eq-\frac{3}{2}$ and $v
eq8$)