Question

simplify.
$\frac{y}{-2}-4>3$
$+4 quad +4$
add 4 on both sides.
$\frac{y}{-2}>7$
$\frac{y}{-2}(-2)<7(-2)$
multiply by $-2$ on both sides. reverse the symbol.
$y < square$

Explanation:

Step1: Add 4 to both sides

$\frac{y}{-2} - 4 + 4 > 3 + 4$
$\frac{y}{-2} > 7$

Step2: Multiply by -2, reverse inequality

$\frac{y}{-2} \times (-2) < 7 \times (-2)$

Step3: Simplify both sides

$y < -14$

Answer:

$y < -14$