Question

simplify. express your answer using exponents.
$(j^{-1}k^{-4})^{1}$

Explanation:

Step1: Apply exponent power rule

Recall the rule $(a^m b^n)^p = a^{m \cdot p} b^{n \cdot p}$. Here $p=1$, so:
$$(j^{-1}k^{-4})^1 = j^{-1 \cdot 1}k^{-4 \cdot 1}$$

Step2: Simplify the exponents

Calculate the products in the exponents:
$$j^{-1 \cdot 1}k^{-4 \cdot 1} = j^{-1}k^{-4}$$

Answer:

$j^{-1}k^{-4}$