Question

simplify. express your answer using positive exponents.
$p^{0} \cdot p^{-21} \cdot p^{-1}$

Explanation:

Step1: Use exponent rule \(a^m \cdot a^n = a^{m + n}\)

\(p^0 \cdot p^{-21} \cdot p^{-1}=p^{0 + (-21)+(-1)}\)

Step2: Calculate the exponent

\(0+(-21)+(-1)= -22\), so we have \(p^{-22}\)

Step3: Use rule \(a^{-n}=\frac{1}{a^n}\) to make exponent positive

\(p^{-22}=\frac{1}{p^{22}}\)

Answer:

\(\frac{1}{p^{22}}\)