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solve for g. g² - 10g + 9 = 0 write each solution as an integer, proper…

Question

solve for g.
g² - 10g + 9 = 0
write each solution as an integer, proper fraction, or improper fraction in simplest form. if there are multiple solutions, separate them with commas.
g =

Explanation:

Step1: Factor the quadratic equation

We need to find two numbers that multiply to 9 and add up to - 10. The numbers are -9 and -1. So, $g^{2}-10g + 9=(g - 9)(g - 1)=0$.

Step2: Set each factor equal to zero

If $(g - 9)(g - 1)=0$, then either $g-9 = 0$ or $g - 1=0$.
For $g-9 = 0$, we get $g=9$.
For $g - 1=0$, we get $g=1$.

Answer:

$1,9$