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solve for j. 9 ≥ 17 - j

Question

solve for j.
9 ≥ 17 - j

Explanation:

Step1: Subtract 17 from both sides

$9 - 17 \geq 17 - j - 17$
$ -8 \geq -j$

Step2: Multiply both sides by -1 (reverse inequality)

$(-1)\times(-8) \leq (-1)\times(-j)$
$8 \leq j$
Which is equivalent to $j \geq 8$

Answer:

$j \geq 8$